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1 kg weight is suspended to a weightless spring and it has time period T. If now 4 kg weight is suspended from the same spring the time period will beA. TB. `T//2`C. `2T`D. 4T |
Answer» Correct Answer - C `T_(1)=2pisqrt((m)/(k))=2pisqrt((1)/(k))` `T_(2)=2pisqrt((4)/(k))=2pixx2sqrt((1)/(k))` `(T_(2))/(T_(1))=(2)/(1) therefore T_(2)=2T_(1)=2T` |
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