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1 kg weight is suspended to a weightless spring and it has time period T. If now 4 kg weight is suspended from the same spring the time period will beA. TB. `T//2`C. `2T`D. `4T` |
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Answer» Correct Answer - C `T_(1)=2pisqrt((m_(1))/(k))andT_(2)=2pisqrt((m_(2))/(k))` `(T_(2))/(T_(1))=sqrt((m_(2))/(m_(1)))=sqrt((4)/(1))` `T_(2)=2T_(1)` |
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