1.

1 lit of oxygen and 3 lit of SO_(2) at STP are reacted to produce sulphur trioxide . Then the ratio of between volume of sulphur trioxide and that of sulphur dioxide after reaction and weight of SO_3 formed (in grams) respectively are

Answer»

`1:2 , 7:14 gms`
`2:1 , 14.28 gms`
`2:1 , 7.14 gms`
`1:1 , 14.28 gms`

Solution :`2SO_(2)+O_(2)rarr2SO_(3)`
2 lit `LARR` 1 lit `larr` 2 lit
IMPLIES 1 lit `SO_(2)` left
`therefore (SO_(3))/(SO_(2))=(2)/(1)`
WEIGHT of `SO_(3)=(2)/(22.4)xx80=7.14g`


Discussion

No Comment Found