1 litre of N_(2) and 7/8 litre of O_(2) at the same temperature and pressure were mixed together. What is the relationship between the masses of the two gases in the mixture ?

1 litre of N_(2) and 7/8 litre of O_(2) at the same temperature and pr

1.	1 litre of N_(2) and 7/8 litre of O_(2) at the same temperature and pressure were mixed together. What is the relationship between the masses of the two gases in the mixture ?
Answer» Solution :`PV=nRT=(w)/(M)RT` For`N_(2),"" Pxx1=(w_(N_(2)))/(28)xxRT ""`……(i) For`O_(2), "" Pxx(7)/(8)=(w_(N_(2)))/(32)xxRT ""`......(II) Dividing eqn.(ii) by eqn. (i) `(7)/(8)=(w_(O_(2)))/(32)XX(28)/(w_(N_(2)))`. This give `w_(N_(2))=w_(O_(2))` Thus, the MIXTURE contains equal masses of `N_(2)` and `O_(2)`.