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1 litre of N_(2) and 7/8 litre of O_(2) at the same temperature and pressure were mixed together. What is the relationship between the masses of the two gases in the mixture ?

Answer» <html><body><p></p>Solution :`PV=nRT=(w)/(M)RT` <br/> For`N_(2),"" Pxx1=(w_(N_(2)))/(<a href="https://interviewquestions.tuteehub.com/tag/28-299271" style="font-weight:bold;" target="_blank" title="Click to know more about 28">28</a>)xxRT ""`……(i)<br/> For`O_(2), "" Pxx(7)/(<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>)=(w_(N_(2)))/(32)xxRT ""`......(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) <br/> Dividing eqn.(ii) by eqn. (i)<br/> `(7)/(8)=(w_(O_(2)))/(32)<a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a>(28)/(w_(N_(2)))`. This give `w_(N_(2))=w_(O_(2))` <br/> Thus, the <a href="https://interviewquestions.tuteehub.com/tag/mixture-1098735" style="font-weight:bold;" target="_blank" title="Click to know more about MIXTURE">MIXTURE</a> contains equal masses of `N_(2)` and `O_(2)`.</body></html>


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