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1 litre of `N_(2) " and " 7//8` litre of `O_(2)` at the same temperature and pressure were mixed together. What is the relation between the masses of the two gases in the mixture ?A. `M_(N_(2)) = 3M_(O_(2))`B. `M_(N_(2)) = 8M_(O_(2))`C. `M_(N_(2)) = M_(O_(2))`D. `M_(N_(2)) = 16 M_(O_(2))` |
Answer» Correct Answer - C `PV = (M)/(m) RT` `P xx 1 = (M_(N_(2)))/(28) RT`....(i) `P xx (7)/(8) = (M_(O_(2)))/(32)RT` ....(ii) Dividing eq. (i) by e. (ii), we get `M_(N_(2)) = M_(O_(2))` |
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