1.

1 mol N_2 and 3 mol H_2 taken in 4L definite temperature of closed vessel. Reaction N_(2(g)) + 3H_(2(g)) hArr2NH_(3(g)) according to 0.25% N_2 convert into ammonia. Calculate K_c and how much reaction of K_c? 1/2N_(2(g)) + 3/2 H_(2(g)) hArr NH_(3(g))

Answer»

SOLUTION :`K_c=1.49xx10^(-5) ("mol L"^(-1) )^(-2)` and `K_c=3.86xx10^(-3) ("mol L"^(-1))`


Discussion

No Comment Found