1 mol of CH_(4), 1 mole of CS_(2) and 2 mol of H_(2)S are 2 mol of H_(2) are mixed in a 500 ml flask The equilibrium constant for the reaction K_(C)=4xx10^(-2)"mol"^(2)" lit"^(-2). In which direcition will the reaction proceed to reach equilibrium ?

1 mol of CH_(4), 1 mole of CS_(2) and 2 mol of H_(2)S are 2 mol of H_(

1.	1 mol of CH_(4), 1 mole of CS_(2) and 2 mol of H_(2)S are 2 mol of H_(2) are mixed in a 500 ml flask The equilibrium constant for the reaction K_(C)=4xx10^(-2)"mol"^(2)" lit"^(-2). In which direcition will the reaction proceed to reach equilibrium ?
Answer» <html><body><p></p>Solution :`CH_(4)(g)+2H_(2)S(g)hArrCS_(2)(g)+4H_(2)(g)` <br/> `K_(C)=4xx10^(-2)" <a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a> <a href="https://interviewquestions.tuteehub.com/tag/lit-537267" style="font-weight:bold;" target="_blank" title="Click to know more about LIT">LIT</a>"^(-2)` <br/> `"Volume = 500 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>"=1/2L` <br/> `{:([CH_(4)]_("in")=("1 mol")/(1)""[CS_(2)]_("in")=("1 mol")/(1/2L)),("= 2 mol L"^(-1)"= 2 mol L"^(-1)),([H_(2)S]_("in")=("2 mol")/(1/2L)""[H_(2)]=("2 mol")/(1/2L)),("= 4 mol L"^(-1)"= 4 mol L"^(-1)):}`<br/> `Q=([CS_(2)][H_(2)]^(4))/([CH_(4)][H_(2)S]^(2))` <br/> `:.Q=(2xx(4)^(4))/((2)xx(2)^(2))=64` <br/> `QgtKC` <br/> The reaction will proceed in the reverse direation to reach the equilibrium.</body></html>