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1 mol of CH_4, 1 mole of CS_2 and 2 mole of H_2S are 2 mol of H_2 are mixed in a 500 mL flask. The equilibrium constant for the reaction K_C = 4 xx 10^(-2) mol^2 lit^(-2). In which direaction will the reaction proceed to reach equilibrium ? |
Answer» <html><body><p></p>Solution :`CH_4 (g)+ 2H_2S (g) hArr CS_2(g) + 4H_2(g)`<br/> `K_C =<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>) mol^2 L^(-2)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a>`= 500 mL= 1/2 L` <br/> `[CH_4]= (1 mol)/(1/2L) = 2mol L^(-1)`<br/> `[CS_2] = (1 mol)/(1/2L) = 2mol L^(-1)`<br/> `[H_2S] = (2 mol)/(1/2L) = 4mol L^(-1)`<br/> `[H_2]= (2mol)/(1/2L) = 4 mol L^(-1)` <br/> `Q = ([CS_2][H_2]^4)/([CH_4][H_2S]^2)` <br/> `:. Q = (2 xx (4)^4)/(2 xx (4)^2) = 16` <br/> `Q gt K_C` <br/> `:.` The reaction will <a href="https://interviewquestions.tuteehub.com/tag/proceed-592932" style="font-weight:bold;" target="_blank" title="Click to know more about PROCEED">PROCEED</a> in the reverse direction to <a href="https://interviewquestions.tuteehub.com/tag/reach-1178062" style="font-weight:bold;" target="_blank" title="Click to know more about REACH">REACH</a> the equilibrium.</body></html> | |