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1 mol of iron (Fe) reacts completely with 0.65 mol O, togive a mixture of only FeO and Fe,0,. Mole ratio offerrous oxide to ferric oxide is :(A) 3:2(B) 4:3(C) 20:13(D) none of these |
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Answer» Answer: 4:3 Explanation: 1 mol of IRON (Fe) reacts completely with 0.65 mol O, to give a MIXTURE of only FeO and Fe,0,. Mole ratio of ferrous oxide to ferric oxide is : 2Fe + O2 ==> 2FeOa a/2 MOLES a 4Fe +3O2 ===> 2Fe2O3 b 3b/4 moles b/2 a+ b = 1 a/2 + 3b/4 = 0.65 or 1/2 a+ 1/2 b = 1/2 ( I SUBSTITUTE the FIRST equation with 1/2) a/2 + 3b/4 = 0.65 ==> b = 0.6 moles a= 0.4 moles --> moles FeO = 0.4 moles moles Fe2O3 = 0.6/2 = 0.3 moles ===> Ratio = 0.4/0.3 = 4/3 |
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