1 mol of NH_(3) gas( gamma = 1.33) at 27^(@)Cis allowed to expand adiabatically so that the final volume becomes 8 times. Work done will be

1 mol of NH_(3) gas( gamma = 1.33) at 27^(@)Cis allowed to expand adia

1.	1 mol of NH_(3) gas( gamma = 1.33) at 27^(@)Cis allowed to expand adiabatically so that the final volume becomes 8 times. Work done will be
Answer» <html><body><p>450 cal<br/> 1800 cal<br/>900 cal<br/>300 cal</p>Solution :Work done in <a href="https://interviewquestions.tuteehub.com/tag/adiabatic-849856" style="font-weight:bold;" target="_blank" title="Click to know more about ADIABATIC">ADIABATIC</a> expansion` = - nC_(v) (T_(2) -T_(1))`. To calculate <a href="https://interviewquestions.tuteehub.com/tag/final-461168" style="font-weight:bold;" target="_blank" title="Click to know more about FINAL">FINAL</a> tem. `T_(2)`, proceeding as in the above case, `T_(2) = 150 <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>`.<br/> `C_(v)` for `NH_(3)= 3R` <br/> `( NH_(3)` is a non-linear molecule with`N=4` .<a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, translational degrees`=3`, Rotational degrees`=3`. Total `U = ( 3)/(2) RT + (3)/(2)RT =3RT`) <br/> `:. w=-1 xx3 xx2(150-300) = 900cal`</body></html>