1 mol of NH_(3) gas( gamma = 1.33) at 27^(@)Cis allowed to expand adiabatically so that the final volume becomes 8 times. Work done will be

1 mol of NH_(3) gas( gamma = 1.33) at 27^(@)Cis allowed to expand adia

1.	1 mol of NH_(3) gas( gamma = 1.33) at 27^(@)Cis allowed to expand adiabatically so that the final volume becomes 8 times. Work done will be
Answer» 450 cal 1800 cal 900 cal 300 cal Solution :Work done in ADIABATIC expansion` = - nC_(v) (T_(2) -T_(1))`. To calculate FINAL tem. `T_(2)`, proceeding as in the above case, `T_(2) = 150 K`. `C_(v)` for `NH_(3)= 3R` `( NH_(3)` is a non-linear molecule with`N=4` .HENCE, translational degrees`=3`, Rotational degrees`=3`. Total `U = ( 3)/(2) RT + (3)/(2)RT =3RT`) `:. w=-1 xx3 xx2(150-300) = 900cal`