1.

1 mole Ba(OH)_(2) will exactly neutralize

Answer»

0.5 MOLE HCl
1 mole `H_(2)SO_(4)`
1 mole of `H_(3)PO_(3)`
2 mole of `H_(3)PO_(2)`

Solution :1 Mole `BA(OH)_(2)` = 2 equivalents `Ba(OH)_(2)`
1 mole HCl = 1 EQUIVALENT HCl
1 mole `H_(3)PO_(3)` (di-basic acid)
= 2 equivalent `H_(3)PO_(3)`
1mole `H_(3)PO_(2)` (monobasic acid)
= 1 equivalent `H_(3)PO_(2)`


Discussion

No Comment Found

Related InterviewSolutions