1 mole each of CaC_(2), Mg_(2)C_(3) reacts with excess water in separate open flasks work done by the gas during the dissolution shows the order:

1 mole each of CaC_(2), Mg_(2)C_(3) reacts with excess water in separa

1.	1 mole each of CaC_(2), Mg_(2)C_(3) reacts with excess water in separate open flasks work done by the gas during the dissolution shows the order:
Answer» `CaC_(2) = Mg_(2)C_(3) lt Al_(4)C_(3)` `CaC_(2) = Mg_(2)C_(3) = Al_(4)C_(3)` `Mg_(2)C_(3) lt CaC_(-2) lt Al_(40C_(3)` `Mg_(2)C_(3) lt Al_(4)C_(3) lt CaC_(2)` Solution :`CaC_(2) RARR C_(2)H_(2)` `Mg_(2)C_(3) rarr C_(3)H_(4)` `Al_(4)C_(3) rarr CH_(4)`