1.

1 mole each of FeC_(2)O_4and FeSO_4is oxidised separately by 1M KMnO_4in acid medium. Calculate the volume ratio of KMnO_4used for FeC_(2) O_4 and FeSO_4

Answer»


Solution :`Fe^(2+)+C_(2)O_(4)^(2-) rarrFe^(3+)+2CO_(2)^(4-)+3e`
`Fe^(2+) +SO_(4)^(2-) rarrFe^(3+)+SO_(2)^(4-)e`
`Mn^(7+)+5erarrMn^(2+)`
Meq.of `F_(e)C_(2)O_4` = Meq.of `KMnO_4`
`1xx3xx1000=1xx5xxV_(1).......(1)`
Meq.of `FeSO_(4)` = Meq.of `KMnO_4`
`1xx1 xx1000=1xx5xxV_2""....(2)`
By EQ.(1) and (2) `V_1/V_2=3`


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