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1 mole each of FeC_(2)O_4and FeSO_4is oxidised separately by 1M KMnO_4in acid medium. Calculate the volume ratio of KMnO_4used for FeC_(2) O_4 and FeSO_4 |
Answer» <html><body><p><br/></p>Solution :`Fe^(2+)+C_(2)O_(4)^(2-) rarrFe^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>+)+2CO_(2)^(4-)+3e` <br/> `Fe^(2+) +SO_(4)^(2-) rarrFe^(3+)+SO_(2)^(4-)e` <br/> `Mn^(<a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>+)+5erarrMn^(2+)` <br/> Meq.of `F_(e)C_(2)O_4` = Meq.of `KMnO_4` <br/> `1xx3xx1000=1xx5xxV_(1).......(1)` <br/> Meq.of `FeSO_(4)` = Meq.of `KMnO_4` <br/> `1xx1 xx1000=1xx5xxV_2""....(2)` <br/> By <a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>.(1) and (2) `V_1/V_2=3`</body></html> | |