1 mole of a non-voltile non-dissociative solid solute is dissolved in 200 moles of water. The solution is taken to a temperature T_(K) (lower than freezing point of solution) to cause ice formation. After removal of ice the remaining solution is taken to 373 K where vapour pressure is observed is to be 740 mm of Hg. Identify the correct options : Given data : K_(f) (H_(2)O) = 2K kg mol^(-1) and normal boiling point of H_(2)O = 373 K.

1 mole of a non-voltile non-dissociative solid solute is dissolved in

1.	1 mole of a non-voltile non-dissociative solid solute is dissolved in 200 moles of water. The solution is taken to a temperature T_(K) (lower than freezing point of solution) to cause ice formation. After removal of ice the remaining solution is taken to 373 K where vapour pressure is observed is to be 740 mm of Hg. Identify the correct options : Given data : K_(f) (H_(2)O) = 2K kg mol^(-1) and normal boiling point of H_(2)O = 373 K.
Answer» `163` moles of ice will be formed. Temperture to which original solution was colled should be `(2000)/(37 XX 18)K`. FREEZING POINT of orignial solution should be `-(10)/(18).^(@)C`. Ralative lowering of VAPOUR pressure of final solution will be `(1)/(201)`. Answer :A::C