1 mole of an ideal gas, maintained at 4.1 atm and at a certain temperature , absorbs heat 3710 J and expands to 2 litres . Calculate the entropy changes in expansion process.

1 mole of an ideal gas, maintained at 4.1 atm and at a certain tempera

1.	1 mole of an ideal gas, maintained at 4.1 atm and at a certain temperature , absorbs heat 3710 J and expands to 2 litres . Calculate the entropy changes in expansion process.
Answer» SOLUTION :PRESSURE of an ideal gas =`P_i` = 4.1 atm. EXPANSION in volume `DeltaV` = 2 litres Heat absorbed =Q = 3710 J Entropy change = `DeltaS` = ? For an ideal gas PV = RT for one mole . `T=(PV)/R=(4.1xx2)/0.0830=100^@C` T=100+273 = 373 K `DeltaS=q/T_((K))=3710/373` Entropy change =9.946 `JK^(-1)`