1 mole of an ideal gas, maintained at 4.1 atm and at a certain temperature, absorbs heat 3710 J and expands to 2 litres. Calculate the entropy change in expansion process.

1 mole of an ideal gas, maintained at 4.1 atm and at a certain tempera

1.	1 mole of an ideal gas, maintained at 4.1 atm and at a certain temperature, absorbs heat 3710 J and expands to 2 litres. Calculate the entropy change in expansion process.
Answer» SOLUTION :`n=1"mole"` `P=4.1atm` `V=2" LIT"` `T=?` `q=3710J` `DeltaS=(q)/(T)` `DeltaS=(q)/(((PV)/(NR)))` `DeltaS=(nRq)/(PV)` `DeltaS=(1xx0.082" lit atm "K^(-1)xx3710J)/(4.1" atm"xx2" lit")` `DeltaS=37.10JK^(-1)`.