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1 mole of Rhombic sulphur is treated with conc. `HNO_(3)` find the mass of `H_(2)O` formed |
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Answer» Correct Answer - 288 `32H_(2)O+S_(8)to8H_(2)SO_(4)+48H^(o+)+48e^(Theta)` `underline([e^(Theta)+H^(o+)+HNO_(3)toNO_(2)+H_(2)O]xx48)` `underset(1 mol)(S_(8))+48HNO_(3)to8H_(2)SO_(4)+48NO_(2)+underset(16" mol")(16H_(2)O)` `implies` mass of `H_(2)O` formed `=(16)(18)g=288g` |
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