1.

`1 mu C` charge is shifted from A to B, and it is found that work done by an external force is `40 mu J`. In doing so against electrostatic forces, find potential difference `V_A - V_B`.

Answer» `(W_(AB))_("ext")=q(V_(B)-V_(A))" "implies" "40 muJ=1 muC (V_(B)-V_(A))" "implies" "V_(A)-V_(B)=-40 V`


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