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1. nadius of Boho's \( 4^{\text {th }} \) onbit fon t 1 atom |
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Answer» We Know that, r = 0.529 x \(\frac{n^2}{z}\)pm Where, n = Orbit Number (Principle Quantum Number) z = Atomic Number ∴ r = 0.529 x \(\frac{4^2}{1}\) = 0.529 x 4 x 4 = 8.464 pm its ans is 0.85 by formula... n2/z2 × 0.53 42/12 ×0.53 we get nearly 0.85.
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