1.

`1` of `NO_(2)` and `7//8 L` of `O_(2)` at the same temperature and pressure were mixed together. What is the relation between the mases of the two gases in the mixture?A. `M_(N_(2))=3M_(O_(2))`B. `M_(N_(2))=8M_(O_(2))`C. `M_(N_(2))=M_(O_(2))`D. `M_(N_(2))=16M_(O_(2))`

Answer» `PV=(M)/(m)RT`
`Pxx1=(M_(N_(2)))/(28)RT`
`Pxx(7)/(8)=(M_(O_(2)))/(32)RT`
Dividing equation (`i`) by (`ii`), we get
`M_(N_(2))=M_(O_(2))`


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