1 ohm resistance is in series with a Ammeter which is balanced by 75 cm of potentiometer wire. A standard cell of 1.02 V is balanced by 50 cm.t he ammeter shows a reading of 1.5 A. The error in the ammeter reading isA. 0.002 AB. 0.03 A `P_(1)` to `P_(2)`C. 1.01 AD. no error

1 ohm resistance is in series with a Ammeter which is balanced by 75 c

1.	1 ohm resistance is in series with a Ammeter which is balanced by 75 cm of potentiometer wire. A standard cell of 1.02 V is balanced by 50 cm.t he ammeter shows a reading of 1.5 A. The error in the ammeter reading isA. 0.002 AB. 0.03 A `P_(1)` to `P_(2)`C. 1.01 AD. no error
Answer» Correct Answer - B `(V_(1))/(V_(2))=(l_(1))/(l_(2))=(75)/(50)impliesV_(1)=1.53V` `I_(1)=(V_(1))/(I)=1.53A`, error `=1.53-1.50=0.03`

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1 ohm resistance is in series with a Ammeter which is balanced by 75 cm of potentiometer wire. A standard cell of 1.02 V is balanced by 50 cm.t he ammeter shows a reading of 1.5 A. The error in the ammeter reading isA. 0.002 AB. 0.03 A `P_(1)` to `P_(2)`C. 1.01 AD. no error

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