1.

(1-omega)(1-omega^2)(1-omega^4)(1-omega^5)=9

Answer»

SOLUTION :L.H.S.`=(1-omega)(1-omega^2)(1-omega^4)(1-omega^5)`
`=(1-omega)(1-omega^2)(1-omega)(1-omega^2)`
(1-omega)^2(1-omega^2)^2`
`={(1-omega)(1-omega^2)}^2`
`=(1-omega^2-omega+omega^3)^2`
`{3-(omega^2+omega+1)^2`
`(3)^2=9=R.H>S` (PROVED)


Discussion

No Comment Found

Related InterviewSolutions