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(1-omega+omega^2)(1-omega^2+omega^4)(1-omega^4+omega^2)….to 2nFactors =2^(2n) |
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Answer» SOLUTION :`L.H.S.=(1-omega+omega^2)(1-omega^2+omega^4)(1-omega^4+omega^2"…….to 2N FACTORS."` `=(-omega-omega)1-omega^2+omega)(1-omega+omega^2)"……to 2n factors."` `=(-2omega)(-omega^2-omega^2)(-omega-omega)"……to 2n factors"` `=[(-2omega)(-2omega)"………to n factors]"XX[(-2omega^2)(-2omega^2)"......to n factors."]` `=(-2omega)^nxx(-2omega^2)^n=(4omega^3)^n=4^n=2^(2n)`"=R.H.S.(PROVED)" |
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