1.

(1-omega +omega^2)(1+omega-omega^2)=4

Answer»

SOLUTION :L.H.S.`=(1-omega+omega^2)(1+omega-omega^2)`
`= (-omega-omega)(-omega^2-omega^2)(:' 1+omega+omega^2=0)`
`(-2omega-2omega^2)=4omega^3=4=`R.H.S.


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