Saved Bookmarks
| 1. |
(1 + sin θ/ 1 - sin θ) + (1 - sin θ/1 + sin θ)\(\frac{1+sin\theta}{1-sin\theta}+\frac{1-sin\theta}{1+sin\theta}\) |
|
Answer» \(\frac{1+sin\theta}{1-sin\theta}+\frac{1-sin\theta}{1+sin\theta}\) = \(\frac{(1+sin\theta)^2+(1-sin\theta)^2}{1-sin^2\theta}\) = \(\frac{1+sin^2\theta+2sin\theta + 1+sin^2\theta-2sin\theta}{cos^2\theta}\) \(=\frac{2(1+sin^2\theta)}{cos^2\theta}\) = 2(sec2 θ + tan2θ) = 2(1 + 2 tan2θ) = 2 + 4 tan2θ |
|