1.

1/(sin(theta) %2B 1) %2B 1/(-sin(theta) %2B 1)=2*sec(theta)^2

Answer»

1/ 1+ sinA + 1/ 1-sinA= 1-sinA+1+SinA/(1+sinA)(1-sinA)=2/1-sinA^2=2/cosA^2=2secx^2



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