1.

((1+sin theta+icos theta)/(1+sin theta - icos theta))^(n)=

Answer»

`cos ((N pi)/(2)-n theta)+ISIN((npi)/(2)-n theta)`
`cos ((n pi)/(2)+n theta)+isin((npi)/(2)+n theta)`
`sin ((n pi)/(2)-n theta)+icos((npi)/(2)-n theta)`
`cosn (( pi)/(2)+ 2theta)+isin n((pi)/(2)+ 2theta)`

Answer :A


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