(1) Six year before, the age of mother was equal to the square of her

1.	(1) Six year before, the age of mother was equal to the square of her son'soge. Thrce year hence, her age vill he thrice he age of her son them.Find the present ages of the mother and son.
Answer» Explanation - Six years ago let the son age = x Mother = x² Present ages now: Son = x + 6 Mother = x² + 6 3 years later: Son = x + 6 + 3 = x + 9 Mother = x² + 6 + 3 = x² + 9 Solving x - x² + 9 = 3(x + 9) x² + 9 = 3x + 27 x² - 3x - 18 = 0 (x - 6)(x + 3) = 0 x = 6 or x = -3 Take x = 6. As the other value is (- value) Finding their Present age - Son = x + 6 = 6 + 6 = 12 years. Mother = x² + 6 = (6)² + 6 = 42 years. Hence : Son = 12 years Mother = 42 years

(1) Six year before, the age of mother was equal to the square of her son'soge. Thrce year hence, her age vill he thrice he age of her son them.Find the present ages of the mother and son.

Answer»

Explanation -

Six years ago let the son age = x

Mother = x²

Present ages now:

Son = x + 6

Mother = x² + 6

3 years later:

Son = x + 6 + 3 = x + 9

Mother = x² + 6 + 3 = x² + 9

Solving x -

x² + 9 = 3(x + 9)

x² + 9 = 3x + 27

x² - 3x - 18 = 0

(x - 6)(x + 3) = 0

x = 6 or x = -3

Take x = 6. As the other value is (- value)

Finding their Present age -

Son = x + 6 = 6 + 6 = 12 years.

Mother = x² + 6 = (6)² + 6 = 42 years.

Hence :

Son = 12 years

Mother = 42 years