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1)Sixyearbefor,teageofmotherwassquare of her sonage. Three year hence, her age will be thrice the age of her son thenFind the present ages of the mother and son. |
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Answer» suppose current ages are m and s so six years before (m-6) = (s-6)(s-6) m-6 = s*s-12s+36 m = s*s-12s+42 after three years m+3 = 3(s+3) m = 3s + 6 so 3s+6 = s*s -12s + 42 s*s - 15s + 36 = 0 (s-12)(s-3)=0 so s=3 then m=15 or s=12 then m=42 |
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