InterviewSolution
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InterviewSolution
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`1/(sqrt((12-sqrt(140))))-1/(sqrt((8-sqrt(60))))-2/(sqrt(10+sqrt(84)))` का मान ज्ञात करें। |
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Answer» Correct Answer - A `1/(sqrt((12-sqrt(140))))-1/(sqrt((8-sqrt(60))))` `2/(sqrt((10+sqrt(84))))` `implies1/(sqrt(12-sqrt(4xx35)))-1/(sqrt(8-sqrt(4xx15)))` `-2/(sqrt(10+sqrt(4xx21)))` `implies1/(sqrt(12-2sqrt(35)))-1/(sqrt(8-2sqrt(15)))-2/(sqrt(10+2sqrt(21)))` `implies 1/(sqrt((sqrt(7))^(2)+(sqrt(5))^(2)-2sqrt(7)sqrt(5)))-1/(sqrt((sqrt(5)^(2)+(sqrt(3)^(2)-sqrt(5)sqrt(3)))-` `2/(sqrt((sqrt(7))^(2)+(sqrt(3))^(2)-2sqrt(7)sqrt(3)))` `implies1/(sqrt((sqrt(7)-sqrt(5))^(2)))1/(sqrt((sqrt(5)-sqrt(3))^(2)))-2/(sqrt((sqrt(7)+sqrt(3))^(2)))` `implies1/(sqrt(7)-sqrt(5))-1/(sqrt(5)-sqrt(3))-2/(sqrt(7)-sqrt(3))` Relationlizing in above equation. `implies1/(sqrt(7)-sqrt(5))xx(sqrt(7)+sqrt(5))/(sqrt(7)+sqrt(5))-1/(sqrt(5)-sqrt(3))xx` `(sqrt(5)+sqrt(3))/(sqrt(5)+sqrt(3))-2/(sqrt(7)+sqrt(3))xx(sqrt(7)-sqrt(3))/(sqrt(7)-sqrt(3))` `implies (sqrt(7)+sqrt(5))/2-((sqrt(5)+sqrt(3)))/2-((sqrt(7)-sqrt(3)))/2` `implies sqrt(7)+sqrt(5)-sqrt(5)-sqrt(3)-sqrt(7)+sqrt(3)/2` `implies0` |
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