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1, tanl°tan2°tan3°tan 4° ... (870 89% का मान होगा : . (b) 0. © L |
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Answer» Let's take tan 89 and tan 1 in the first case and Let's take Tan 2 and tan 88 in 2nd case:-By the Problem,[1st case]:-=) tan(90-89)tan89=) cot89 x tan89=) 1/tan89 x tan89 [tan89 will be canceled onboth the sides by multiplying]=) 1. Ans. By the Problem,[2nd Case]:-=) tan(90-88) tan88=) cot88 x tan88=) 1/tan88 x tan88 [tan 88 will be canceled onboth the sides by multiplying]=) 1.Ans. Therefore, if we go on doing this for every ratios...we will come to the answer 1 for each case.Hence, Answer = 1. |
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