(1) the energy associated with the first orbit in the hydrogen atom is

1.	(1) the energy associated with the first orbit in the hydrogen atom is -2.18 × 10^-18 J/atom. whT us the energy associated qith yhe fifth orbit ?(2) Calculate the radius of Bohr's fifth orbit for hydrogen atom.
Answer» Answer: Mass (m) = 5 KG Momentum (p) = 10 Kg m/s Force applied (F)= 0.2N for t= 10 seconds Solution: Momentum (p)=m∗u=10Kgm/s (Here u is the VELOCITY at which the object is moving) p=5∗u=10 u=105=2m/s F=m∗a=0.2N ( When force is applied to the moving object then object will accelerate at 'a') F=5∗a=0.2 a=0.25=0.04m∗s−2 Now, using Newton's laws of motion we will FIND the new velocity (v) of the object v=u+a∗t v=2+0.04∗10=2.4m∗s−1 Change in KINETIC energy is ΔK.E=12m∗v2−12m∗u2 ΔK.E=12∗m(v2−u2) ΔK.E=12∗5∗(2.42−22) ΔK.E=0.5∗5∗(5.76−4)=4.4J Increase in kinetic energy will be 4.4 joules.

(1) the energy associated with the first orbit in the hydrogen atom is -2.18 × 10^-18 J/atom. whT us the energy associated qith yhe fifth orbit ?(2) Calculate the radius of Bohr's fifth orbit for hydrogen atom.

Answer»

Answer:

Mass (m) = 5 KG

Momentum (p) = 10 Kg m/s

Force applied (F)= 0.2N for t= 10 seconds

Solution:

Momentum (p)=m∗u=10Kgm/s

(Here u is the VELOCITY at which the object is moving)

p=5∗u=10

u=105=2m/s

F=m∗a=0.2N

( When force is applied to the moving object then object will accelerate at 'a')

F=5∗a=0.2

a=0.25=0.04m∗s−2

Now, using Newton's laws of motion we will FIND the new velocity (v) of the object

v=u+a∗t

v=2+0.04∗10=2.4m∗s−1

Change in KINETIC energy is

ΔK.E=12m∗v2−12m∗u2

ΔK.E=12∗m(v2−u2)

ΔK.E=12∗5∗(2.42−22)

ΔK.E=0.5∗5∗(5.76−4)=4.4J

Increase in kinetic energy will be 4.4 joules.