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1.The expression-cos(x-2) tan-simplifies to3R(D) cos x(C) -(1 cos x)--,72-car 47-sin, 43·sin2 107 is equal to-(B) sinx

Answer»

{tan(x-π/2).cos(3π/2+x)-sin³(7π/2-x)}/{cos(x-π/2)tan(3π/2+x)}=[tan{-(π/2-x)}.cos{(π/2×3)+x}-sin³{(π/2×7)-x}]/[cos{-(π/2-x)}.tan{(π/2×3)+x}=[-tan(π/2-x).sinx-(-cosx)³]/[cos(π/2-x).(-cotx)]=(-cotx.sinx+cos³x)/[sinx.(-cotx)]=[-(cosx/sinx).sinx+cos³x]/[sinx.(-cosx/sinx)]={-cosx(1-cos²x)}/(-cosx)=1-cos²x=sin²x



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