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1. The product of two consecutive natural numbersis 42. Find the numbers.

Answer»

let the numbers be n and n+1,n×(n+1)=42=>n(n+1)=6×7=>n(n+1)= 6(6+1)=> n=6so, the required numbers are 6 and 7

let the first no be xand the second consecutive no be ( x + 1 )according to condition of problem x ( x + 1) = 42x² + x - 42 = 0 -42 /\ -6 7( x - 6 )(x + 7 ) = 0Therefore x = 6 or x = -7but x = -7 is not possible therefore x = 6 the No's are 6 and 7



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