1.The product of twoconsecutive positiveODD integers is 195Find the nu

1.	1.The product of twoconsecutive positiveODD integers is 195Find the numbers
Answer» If these numbers are consecutive odds, they have a difference of 2. So you can represent them by x-1 and x+1 Now (a+b)(a-b)=a^2-b^2 so (x+1)(x-1)=x^2-1^2=x^2-1 So add 1 to the product and you get the square of the number between the two. 195+1=196sqrt(196)=14 So the numbers are 13 and 15. thank you but i didn't understand the method If the product of two consecutive positive odd integers is 225,what is the largest integer

1.The product of twoconsecutive positiveODD integers is 195Find the numbers

Answer»

If these numbers are consecutive odds, they have a difference of 2.

So you can represent them by x-1 and x+1

Now (a+b)*(a-b)=a^2-b^2

so (x+1)*(x-1)=x^2-1^2=x^2-1

So add 1 to the product and you get the square of the number between the two.

195+1=196sqrt(196)=14

So the numbers are 13 and 15.

thank you but i didn't understand the method

If the product of two consecutive positive odd integers is 225,what is the largest integer