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1. Two stones, having masses in the ratio of 3:2, aredropped from the heights in the ratio of 4 9. Theratio of magnitudes of their linear momenta justbefore reaching the ground is (neglect air resistance)(2) 2: 3(4) 1 1(3) 3 2

Answer»

v²=u²+2as here in both case u will be zero

momentum(p)=velocity × mass

here we need v

v=√2as (a=g=10m/s²)

in first case v = √2×10×4 =4√5

p = 4√5 × 3

= 12√5in case 2

v=√2×10×9

= 6√5

p= 6√5 × 2

=12√5HENCE RATIO IS 1:1

answer is d 1:1hope it helps



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