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1. When 22.4 litres of H_2(g) is mixed with 11.2 litres of Cl_2 (g) each at 273 K at 1 atm the moles of HCl (g), formed is equal to.......

Answer»

2 MOLES of HCL (G)
0.5 moles of HCI (g)
1.5 moles of HCl (g)
1 mole of HCl (g)

Solution :1 moleof HCI(g)
Solutionn:` H_2 (g)+ Cl_2(g)to 2HCI (g)`


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