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`(1+x)^(n)=C_(0)+C_(1)x+C_(2)x^(2)+….+C_(n)x^(n)` then `C_(0)C_(2)+C_(1)C_(3)+C_(2)C_(4)+…..+C_(n-2)C_(n)` is equal to :A. `.^(2n)C_(n-1)`B. `.^(n)C_(n-1)`C. `.^(2n)C_(n+1)`D. `.^(n)C_(n+1)` |
| Answer» Correct Answer - A | |