1.

(1 + x)^(n) = p_(0) + p_(1) x + p_(2) x^(2) + … + p_(n) x^(n), then p_(0) + p_(3) + p_(6) + ….. =

Answer»

`(1)/(3) [ 2^(n-1) + cos "" (n PI)/(3)]`
`(2)/(3) [ 2^(n-1) + cos "" (NPI)/(3)]`
` (1)/(3) [2^(n-2) + SIN "" (npi)/(3)]`
`(2)/(3) [2^(n-2) + sin"" (npi)/(6)]`

Answer :B


Discussion

No Comment Found

Related InterviewSolutions