10. 100 ml each 0.5N NaOH, N/5 HCI and N/10 H,SO, are mixed together.

1.	10. 100 ml each 0.5N NaOH, N/5 HCI and N/10 H,SO, are mixed together. The resulting solution will benanidic medium the eauivalent
Answer» 100 mL of 0.5 N NaOH, = 0.100 L x 0.5 N = 0.05 equivalent moles 100 mL of N/5 HCL = 0.100 L x 0.2 N = 0.02 equivalent moles 100 mL of N/10 H2SO4 = 0.100 L x 0.1 N = 0.01 equivalent moles 0.02 equivalent moles of HCl will neutralise 0.02 equivalent moles of NaOH And 0.01 equivalent moles of H2SO4 will neutralise 0.01 equivalent moles of NaOH So unreacted equivalent moles of NaOH = 0.05 - (0.02 + 0.01) = 0.02 The resulting solution will be basic containing 0.02 equivalent moles of NaOH = 0.02 / 0.300 L = 0.067 N NaOH

10. 100 ml each 0.5N NaOH, N/5 HCI and N/10 H,SO, are mixed together. The resulting solution will benanidic medium the eauivalent

Answer»

100 mL of 0.5 N NaOH, = 0.100 L x 0.5 N = 0.05 equivalent moles

100 mL of N/5 HCL = 0.100 L x 0.2 N = 0.02 equivalent moles

100 mL of N/10 H2SO4 = 0.100 L x 0.1 N = 0.01 equivalent moles

0.02 equivalent moles of HCl will neutralise 0.02 equivalent moles of NaOH

And 0.01 equivalent moles of H2SO4 will neutralise 0.01 equivalent moles of NaOH

So unreacted equivalent moles of NaOH = 0.05 - (0.02 + 0.01) = 0.02

The resulting solution will be basic containing 0.02 equivalent moles of NaOH = 0.02 / 0.300 L = 0.067 N NaOH