10^(21) molecules are removed from 440mg of CO_(2). It becomes

1.	10^(21) molecules are removed from 440mg of CO_(2). It becomes
Answer» 366mg 8.3 milli mole 200 mg 4.1 milli mole Solution :`10^(21)` molecules `(0.01)/(6)` MOLES = 73.3 mg 440mg = 0.01 moles `THEREFORE` left over = `0.01-(0.0.1)/(6)` moles = 8.3 moles `=440-73.3mg =366.7mg`

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