10.30 mg of O2 is dissolved into a liter of sea water of density 1.03

1.	10.30 mg of O2 is dissolved into a liter of sea water of density 1.03 g/mL. The concentration of O2 in ppm is__________.
Answer» 1030 gm of sea water contains = 10.3 × 10^–3 gm 10⁶ gm of sea water contains = (10.3 x 10^-3)/1030 x 10⁶ = 10ppm ppm = (10.3 x 10^-3)/1030 x 10⁶ = 10

10.30 mg of O2 is dissolved into a liter of sea water of density 1.03 g/mL. The concentration of O2 in ppm is__________.

Answer»

1030 gm of sea water contains = 10.3 × 10^–3 gm

10⁶ gm of sea water contains = (10.3 x 10^-3)/1030 x 10⁶ = 10ppm

ppm = (10.3 x 10^-3)/1030 x 10⁶ = 10

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10.30 mg of O2 is dissolved into a liter of sea water of density 1.03 g/mL. The concentration of O2 in ppm is__________.

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