InterviewSolution
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InterviewSolution
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`10^(-4)g` of gelatian is required to be added to `100cm^(23)` of a standard gold sol to just prevent its coagulation by the addition of `1cm^(3)` of `10%NaCl` solution to it. Hence the gold number of gelatain isA. `10`B. `1.0`C. `1`D. `0.01` |
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Answer» Correct Answer - D Gold number is the number of milligrams of a lyophilic colloid that will just prevent the precipitation of `10mL` of a gold sol on the addition of `1mL` of `10%` sodium chloride solution. `100cm^(3)` (0r `100mL`) of gold sol required `10^(-4)g` of gelatin. Thus, the amount of gelating needed to protect `10mL` (or `10cm^(3)`) of gold sol will be `(10^(-4)xx10)/(100)=10^(-5)g` `=(10^(-5)g)((1000mg)/(1g))` `=10^(-2)mg` |
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