10^(-4) g of gelatin is required to be added to 100 cm^(3) of a standard gold sol to just prevent its coagulation by the addition of 1 cm^(3) of 10% NaCl solution to it. Hence, the gold number of gelatin is

10^(-4) g of gelatin is required to be added to 100 cm^(3) of a standa

1.	10^(-4) g of gelatin is required to be added to 100 cm^(3) of a standard gold sol to just prevent its coagulation by the addition of 1 cm^(3) of 10% NaCl solution to it. Hence, the gold number of gelatin is
Answer» <html><body><p>10<br/>1<br/>0.1<br/>0.01</p>Solution :By definition, gold number is the number of milligrams of dry <a href="https://interviewquestions.tuteehub.com/tag/protective-1170744" style="font-weight:bold;" target="_blank" title="Click to know more about PROTECTIVE">PROTECTIVE</a> colloids required to just prevent the coagulation of 10mL of red gold sol when 1 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a> (or 1 `cm^(3)` ) of 10% NaCl solution is added to it.<br/> Here the amount of <a href="https://interviewquestions.tuteehub.com/tag/gelatin-471595" style="font-weight:bold;" target="_blank" title="Click to know more about GELATIN">GELATIN</a> required to protect 10 mL (or 10 `cm^(3)`) of gold sol <br/> `=(10^(-4)xx10)/(100)=10^(-<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>) g` <br/> `=10^(-5)xx10^(-3) mg=10^(-2)` mg <br/> =0.01 mg <br/> `therefore` Gold number =0.01</body></html>