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10^(-4) g of gelatin is required to be added to 100 cm^(3) of a standard gold sol to just prevent its coagulation by the addition of 1 cm^(3) of 10% NaCl solution to it. Hence, the gold number of gelatin is |
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Answer» 10 Here the amount of GELATIN required to protect 10 mL (or 10 `cm^(3)`) of gold sol `=(10^(-4)xx10)/(100)=10^(-5) g` `=10^(-5)xx10^(-3) mg=10^(-2)` mg =0.01 mg `therefore` Gold number =0.01 |
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