10.5 cm21 cmIn the above figure, XLMT is a rectangle. LM 21 cm, XL 10.5 cmDiameter of the smaller samicirele is half the diametar of the laregersemicircle. Find the area of non-shaded region.

10.5 cm21 cmIn the above figure, XLMT is a rectangle. LM 21 cm, XL 10.

1.	10.5 cm21 cmIn the above figure, XLMT is a rectangle. LM 21 cm, XL 10.5 cmDiameter of the smaller samicirele is half the diametar of the laregersemicircle. Find the area of non-shaded region.
Answer» Area of semicircle with diameter( AB)= 21cm.Radius of semicircle AB = 21/2 cmDiameter AM= MN= NB (GIVEN)AB = AM+MN+NBAB = AM+AM+AMAB = 3AM21 = 3AMAM= 21/3= 7 cmAM= MN= NB= 7cmArea of Semicircle of diameter AB=πr²/2=[ (22/7)× 21/2×21/2]/2= 693/4 cm²Area of semicircle with diameter AM= area of semicircle diameter MN= Area of semi circle with diameter NBRadius of semicircle with diameter AM,MN,NB= 7/2Area of semicircle with diameter AM,MN,NB=πr²/2= [(22/7)×7/2×7/2]/2= 77/4 cm²Area of shaded region = Area of semicircle with diameter AB - (Area of semicircle with diameter MN) +(Area of semicircle with diameter AM+Area of semicircle with diameter NB)= 693/4 -(77/4) +(77/4 +77/4)= 693/4+77/4= 770/4= 192.5 cm²Hence, the area of the shaded region is 192.5 cm²