10.6 g of pure sodium carbonate if treated with 7.9 g of HCl to produc

1.	10.6 g of pure sodium carbonate if treated with 7.9 g of HCl to produce NaCl, water and carbon dioxide. The mass of NaCl formed is
Answer» Answer: Explanation: Na2CO3 + 2HCl -------> 2NaCl + H20 Here hcl is LIMITING reagent. By mass mass relation, 73g HCl GIVES 117g NACL so 1g--------------->117/73g so 7.9g-------------> 117/73 *7.9 =12.66 gNaCl So, ans is 12.66 g NaCl is produced. Hope it was HELPFUL . Mark it Brainliest.

10.6 g of pure sodium carbonate if treated with 7.9 g of HCl to produce NaCl, water and carbon dioxide. The mass of NaCl formed is

Answer»

Answer:

Explanation: Na2CO3 + 2HCl -------> 2NaCl + H20

Here hcl is LIMITING reagent.

By mass mass relation, 73g HCl GIVES 117g NACL

so 1g--------------->117/73g

so 7.9g-------------> 117/73 *7.9 =12.66 gNaCl

So, ans is 12.66 g NaCl is produced.

Hope it was HELPFUL .

Mark it Brainliest.