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`10^(-6) ` M NaOH is diluted 100 times. The pH of the diluted base isA. between 5 and 6B. between 6 and 7C. between 10 and 11D. between 7 and 8 |
Answer» Correct Answer - D `[OH^(-)]` after dilution `= (10^(-6))/(100)=10^(-8)M` `:. OH^(-)` ions from `H_(2)O` cannot be neglected. Total `[OH^(-)]=10^(-8)+10^(-7)=10^(-8)xx11` `:. pOH=-log(11xx10^(-8))=8-1.04=6.96` `:. pH = 14 - 6.96 = 7.04` |
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