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10. (a) Derive an expression for the rate constant of a firstorder reaction ? How does the rate constant relateto the half life period?(b) Prove that for the first order reaction, the timerequired for 99% completion of the reaction is twicethe time required to complete 90% of the reactions.(C.H.S.E. Instant 2012) |
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Answer» Let's say rate constant of the first order reaction is 'k'. Time taken for the reaction to process is ‘T’. Half life of the reaction ‘t’. Now the reaction is k={ 2.303×log(a/a-x)}/T Now 'a' is initial concentration to find 't' reaction should proceed to half completion. i.e a/2 take in the place of x When you substitute the values we get k=0.693/T As T=t (half reaction). t=0.693/k It is the half life of the reaction with respect to rate constant k For the log the base should be 'e' thanks |
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