Saved Bookmarks
| 1. |
10. A well is dug out whose radius is 4.2 m and depth is 38,m. The earth taken out from well is spread all over atangular field whose dimensions are 130 m x 115 m.Find the rise in the level of field |
|
Answer» Given r = 4.2 m, h = 38 mVolume of well = pi*r*r*h= 22/7*4.2*4.2*38= 22*.6*4.2*38= 21067. 2 m^3 Let rise in level of field = d Then, Volume of Reactangular field= Volume of welll*b*d = 21067.2130*115*d = 21067.2d = 21067.2/(130*115)d = 162/115d = 1.4 m Rise in level of field = 1.4 m |
|