10. A wire hangs vertically under its ownweight. The specific weight o

1.	10. A wire hangs vertically under its ownweight. The specific weight of wire is100 n/m3 and maximum permissibletensile stress is 100 n/mm2. Thegreatest length that can be hung is.(a) 10m(b) 100m(C) 1000m(d) 10,000m
Answer» HEY MATE,ACCORDING TO YOUR QUESTION, A steel WIRE hangs vertically under its own weight. If its density is 8000 kg/m³ and allowable stress is 2000 kg/cm² then how much length it can sustain. stress = 2000 kg/cm² , it is possible as you KNOW BASICALLY, unit of stress is N/m² . if I assume it is written as 2000g N/cm² . we know, stress = force applied/area for a steel wire which is HANGED vertically , force applied = weight = mg mass = VOLUME × density e.g., m = Vd = ALd [ where , A is cross sectional area and L is length ] now, stress = ALd/A = Lgd or, 2000g N/cm² = L × g × 8000kg/m³ [ given density , d = 8000 kg/m³ ] or, 2000 × 10⁴ = 8000L or, L = 2500 m

10. A wire hangs vertically under its ownweight. The specific weight of wire is100 n/m3 and maximum permissibletensile stress is 100 n/mm2. Thegreatest length that can be hung is.(a) 10m(b) 100m(C) 1000m(d) 10,000m

Answer»

HEY MATE,ACCORDING TO YOUR QUESTION,

A steel WIRE hangs vertically under its own weight. If its density is 8000 kg/m³ and allowable stress is 2000 kg/cm² then how much length it can sustain.

stress = 2000 kg/cm² , it is possible as you KNOW BASICALLY, unit of stress is N/m² . if I assume it is written as 2000g N/cm² .

we know, stress = force applied/area

for a steel wire which is HANGED vertically , force applied = weight = mg

mass = VOLUME × density

e.g., m = Vd = ALd [ where , A is cross sectional area and L is length ]

now, stress = ALd/A = Lgd

or, 2000g N/cm² = L × g × 8000kg/m³ [ given density , d = 8000 kg/m³ ]

or, 2000 × 10⁴ = 8000L

or, L = 2500 m

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